Mathematics, 08.07.2019 15:50, abigailb4424

Ray zp bisects ∠ozq so that ∠ozp = 8x – 9 and ∠pzq = 5x + 18. find the value of x, and the measure of each angle. you must show all work in order to receive credit!

Ray zp bisects ∠ozq so that ∠ozp = 8x – 9 and ∠pzq = 5x + 18. find the value of x, and the measure o

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answered: talainalover23

Hi there,
To solve this problem, we first need to state our givens.
Given:
Ray ZP bisects ∠OXQ so that ∠OZP = 8x - 9 and ∠PZQ = 5x + 18
Find: The value of x and the measure of each angle
Ok.. Now that we've stated all our givens and our objective, we can start solving.
Def. of an angle bisector is that it "splits" and angle into two congruent parts.
=> equate the two given expressions together.
8x-9 = 5x+18

Steps to solve this equation:
1. Subtract 5x from both sides:
3x-9=18

2. Add 9 to both sides:
3x=27

3. Divide both sides by 3 to get x value
x = 9

The value of x is 9. To find the value of the ∠OZP and ∠ PZQ, simply plug 9 back into their respective expressions. This results in ∠OZP and ∠PZQ being 63°. This means that the whole angle, ∠OZQ, measures 126 degrees. Hope this helps and have a phenomenal day!

answered: Guest

I'll do the first one for you. it isn't very hard at all.on number one, you have (50 × 3), which equals 150, and (3 × 3), which equals 9. after you establish that, you add 150 and 9 together. so, (150 + 9) equals 159.this means that 53 × 3 = 159.

answered: Guest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: