In how many ways can 3 americans, 4 frenchmen, 4 danes and 2 italians be seated in a row so that those of the same nationality sit together?

165888

Step-by-step explanation:

Given,

Number of americans = 3,

Total way of seating americans in 3 seats = 3 !,

Number of frenchmen = 4,

Total way of seating frenchmen in 4 seats = 4 !,

Number of danes = 4

Total ways of seating danes in 4 seat = 4 !,

Also, number of Italians = 2,

Total ways of seating italians in 2 seats = 2 !,

Hence, the total ways of seating all citizens so that people with same nationality sit together  =  ( 3! × 4! × 4! × 2! ) × 4!

= 6 × 24 × 24 × 2 × 24

= 165888

10 you would take 50/ .2

step-by-step explanation:

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