With < 3 the following two-column proof with missing statement proves that the diagonals of the rectangle bisect each other: statement reason abcd is a rectangle. given line segment ab and line segment cd are parallel | definition of a parallelogram line segment ad and line segment bc are parallel | definition of a parallelogram |alternate interior angles theorem line segment bc is congruent to line segment ad | definition of a parallelogram ∠adb ≅ ∠cbd | alternate interior angles theorem δade ≅ δcbe | angle-side-angle (asa) postulate line segment be is congruent to line segment de cpctc line segment ae is congruent to line segment ce cpctc line segment ac bisects line segment bd definition of a bisector which statement can be used to fill in the blank space? ∠abd ≅ ∠dbc ∠cad ≅ ∠acb ∠bda ≅ ∠bdc ∠cab ≅ ∠acb

∠CAD ≅ ∠ACB

Step-by-step explanation:

The justification states "alternate interior angles theorem."  Alternate interior angles would be inside the parallel lines and on opposite sides of the transversal.  The only pair of angles in our choices that fits this definition is ∠CAD and ∠ACB .

solution:

as, mean is defined as sum of all the observations divided by total number of observations.

and , median is mid value of the data whether arranged in ascending order or descending order.

consider, roadsters:

2,3,4,5,6,7,8,9

mean =

also, median= , because number of observations is even, so median is mean of two mid values.

now, coming to bandits

2,3,4,5,6

mean =  

median = 4, as number of observations is odd.

so, roadsters has greater median as well mean than bandits.

→option a is true about the repairs performed on 2 types of cars:

bandits have lower median and mean than roadsters.

answer: 48

just remember to use pemdas:

parentheses

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