:) ned currently has an account balance of $3,634.51. he opened the account 13 years ago with a deposit of $2,564.65. if the interest compounds twice a year, what is the interest rate on the account? a. 4.7% b. 5.4% c. 2.7% d. 1.4% leroy opened a savings account 18 years ago with a deposit of $2,651.43. the account has an interest rate of 2.8% compounded twice a year. how much interest has leroy earned? a. $4,373.68 b. $2,725.67 c. $4,358.69 d. $1,722.25

Compound interest formula is :

1.

A = 3634.51

p = 2564.65

r = ?

n = 2

t = 13

Putting the values in formula, we get

=>

=>

=>

We get

We get r = 0.02699 and r = -4.02699 (neglecting the negative value)

We get r = 0.027 (rounded)

And in percentage, it is 2.7%.

So, option C is the answer.

2.

p = 2651.43

r = 2.8% or 0.028

n = 2

t = 18

Putting the values in formula we get;

=>

A = $4373.67

So, interest earned = dollars

Hence, option D. $1,722.25 is the answer.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60