Acricket chirps 40 times a minute when the temperature is 50 degrees. write an equation representing the temperature in terms of number of chirps per minute

First we must assume the relationship of the number of chirps and temperature. SO assuming that they are directly proportional, therefore the equation is:

T = k C

where T is temperature, k is proportionality constant, and C is number of chirps

So at T = 50 degrees, C = 40 / min, k is:

50 = k * 40

k = 1.25

So the equation relating the two is:

T = 1.25 C

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5