The 100-meter race times at a state track meet are normally distributed with a mean of 14.62 seconds and a standard deviation of 2.13 seconds. using the standard normal probabilities table, what is the approximate probability that a runner chosen at random will have a 100-meter time less than 15.5 seconds? a.0.1894 b. 0.3409 c. 0.6591 d. 0.7910 e. 0.8106

To solve this problem, we use the t statistic. The formula for z score is:

z = (x – u) / s

where x is the sample value = 15.5 seconds or below, u is the sample mean = 14.62 seconds, s is standard dev = 2.13 seconds

z = (15.5 – 14.62) / 2.13

z = 0.41

Using standard distribution tables at z = 0.41, the value of P is:

P = 0.6591 = 65.91%

Hence there is a 65.91% chance the runner will have less than 15.5 seconds of time

c. 0.6591

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step-by-step explanation:

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45.36 feet per second.

step-by-step explanation:

to find the most accurate determination for the number of feet per second tyrone traveled on his way to work let us convert miles to feet and minutes to seconds.

1 mile = 5280 feet.

1 minute = 60 seconds.

now we will divide 158400 by 3492 to find the most accurate determination for the number of feet per second tyrone traveled on his way to work.

therefore, tyrone traveled on his way to work at the rate of 45.36 feet per second.