Abag contains 42 cups of dog food. your dog eats 2 1 3 cups of dog food each day how many days does the bag of dog food last

divide 42 by 2 1/3

2 1/3 = 7/3

42 / 7/3 =

42 * 3/7 =

126/7 = 18

it will last 18 days

The number of days it will take the dog to consume the 42 cup of food will be 18 days.

To obtain the number of days it will take to consume the entire food :

Hence,

(42 ÷ (7/3))

Take the reciprocal of 7/3 and change the operation sign to multiplication

42 × 3/7 = (42 × 3) / 7 = 126 / 7 = 18 days

Therefore, it will take the dog 18 days to finish up the 42 cups of food.

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there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!