The letters of the alphabet are written on flashcards and dropped into a bag. a flashcard is randomly selected, kept out of the bag, and then another flashcard is randomly selected. which product gives the probability that both cards have a vowel (a, e, i, o, or u) written on them? a. 5/26*4/26 b. 5/26*4/25 c. 5/26*5/25 d. 5/26* 5/26.

First of all, as I told you a little while ago, here is the formula
that solves ALL probability problems.  Memorize this:

Probability =
       (number of different successful possibilities)
divided by
       (total number of all possibilities).

How many cards are in the bag at the beginning ?
One with each letter of the alphabet.  That's 26 .
So the total number of different possible results on the
first draw is 26 .

How many of them are 'successful' ?
A 'successful' card is one with a vowel (a, e, i, o, or u).  That's 5 .
So the probability of pulling a vowel the first time is  5/26 .

Now, we're looking for the probability of pulling TWO vowels, without
replacing the first one.  So what's the situation after the first one ?
If the first one is successful, then when you reach into the bag for
the second draw, there are only 25 total cards in the bag, and
only 4 vowels are left.  So the probability of drawing a vowel the
second time is  4/25 .

The first one was  5/26 .
The second one was  4/25 .

The probability of both of them happening just like that is

             (5/26) x (4/25) .

That looks like choice ' B ' to me.

B. because the 7 represents "seven times", x represents "a number", 12 represents "plus twelve", and -4 represents "minus four"