The population pf a city is 2,500. if the number of males is 240 more than the number of females how many males and females are there in the city

You need to represent the number of males in terms of females.

Since you know the number of males relative to females, it makes sense to represent the number of females as a variable, let's say f.

So then the number of males is f+240 and we know that the number of males plus the number of females is 2500. Knowing this, we can write an equation: f+(f+240)=2500. I put the number of males in brackets there just to make it easy to recognize.

This equation can be condensed into 2f+240=2500 and then solved:

2f=2500−240
f=2500−2402
f=1130

Then, we know the number of females, and we can solve for the number of males from here using our male formula: males=f+240. You should then get 1370 as the number of males.

Checking this answer, we see that 1130 + 1370 does equal 2500.

answer:   n ≤ -3 or n < -5

step-by-step explanation:

-5 + 2n ≥ -11

+5             +5

2n ≥ -6

2/2 ≤ -6/2

n ≤ -3

-6 - 10n > 44

+6           +6

-10n > 50

-10/-10 50/-10

n < -5

t hope this

: