Need asap! algebra 2 ! the admission fee at a fair is $2.50 for children and 5.50 for adults. on a certain day 2220 people entered the fair and $7734 is collected. how many children attended the fair? a.1492 b.1500 c.800 d.728

This is another system of equations problem.

I will use x to represent children and y to represent the adults.

So the two equations you're going to have are:

2.5x + 5.5y = 7734

x + y = 2220.

It's best to use the substitution method here.

Let's take x + y = 2220. Solve for x by subtracting y on both sides.

The equation for x is now x = 2220 - y.

Substitute this into the other equation.

2.5(2220-y) + 5.5y = 7734.

Solve regularly from here.

5550 - 2.5y + 5.5y = 7734.

Combine like terms then divide.

3y = 2184.

y = 728.

Now that you know y, solve for x.

2220 - 728 = x.

x = 1492.

We both know x and y but let's check our answer by plugging the numerical values of both x and y into the equations.

2.5(1492) + 5.5(728) = $7734.
Multiply the numbers.

3730 + 4004 = 7734.

By adding both numbers you'll get 7734 = 7734. So the x and y values are correct.

Looks pretty good to me!