Astudent solved the following problem and made an error: triangles abc and def. angles a and f are congruent and measure 63 degrees. coordinates for the vertices are at a 1, 2 and b 1, 4 and c 3, 3 and d 5, 1 and e 3, 2 and f 5, 3. line 1 segment ab equals 2, segment fd equals 2, segment ab is congruent to segment fd line 2 ∠a ≅ ∠f line 3 length of segment ac. a (1, 2) c (3, 3) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub 1 squared, then d equals square root of quantity 1 minus 3 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1 squared, then d equals square root of 4 plus 1, then d equals square root of 5 segment ac = 2.23 line 4 length of segment ef. e (3, 2) f (5, 3) d equals square root of quantity x sub 2 minus x sub 1 squared plus quantity y sub 2 minus y sub squared then d equals square root of quantity 3 minus 5 all squared plus quantity 2 minus 3 all squared, then d equals square root of negative 2 squared plus negative 1, then d equals square root of 4 plus 1, then d equals square root of 5 segment ef= 2.23 line 5 segment ac is congruent to segment fe line 6 triangle abc is congruent to triangle efdby sas in which line did the student make the first mistake? line 1 line 5 line 6 line 2