Justify the last two steps of the proof. given mn is congruent to segment po and mo is congruent to pn prove mno is congruent to pon proof: 1. mn is congruent to segment po 1. given 2.mo is congruent to 2. given 3. no is congruent to on 3. ? 4.mno is congruent to 4. ? *symmetric property of congruent to; sas *reflexive property of congruent to; sas *symmetric property of congruent to; sss *reflexive property of congruent to; sss

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.