Mathematics

Mathematics, 28.08.2019 06:00, lllmmmaaaooo

Is .375 a rational or irrational number?

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Mathematics, 02.07.2019 12:10, khaekhae10

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational.

Answers: 2

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Mathematics, 03.08.2019 03:30, dkdk31

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

Answers: 1

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Mathematics, 18.09.2019 21:00, erickamurillo9929

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

Answers: 1

Предмет

Mathematics, 18.10.2019 19:00, noahdwilke

Below is a proof showing that the sum of a rational number and an irrational number is an irrational number. let a be a rational number and b be an irrational number. assume that a + b = x and that x is rational. then b = x – a = x + (–a). x + (–a) is rational because however, it was stated that b is an irrational number. this is a contradiction. therefore, the assumption that x is rational in the equation a + b = x must be incorrect, and x should be an irrational number. in conclusion, the sum of a rational number and an irrational number is irrational. which of the following best completes the proof? it is the sum of two rational numbers. it is the sum of two irrational numbers. it represents a non-terminating, non-repeating decimal. its terms cannot be combined.

Answers: 3

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