Solve the system by the elimination method. check your work. 2a + 3b = 6 5a + 2b - 4 = 0 make sure there are no spaces in your answer. include a comma in your answer. {( a0 )}

From the computation, a will be 0 and b will be 2.

The equations given are:

2a + 3b = 6

5a + 2b = 4

Multiply equation i by 2

Multiply equation ii by 3

4a + 6b = 12

15a + 6b = 12

Subtract the equations

a = 0

Since 2a + 3b = 6

2(0) + 3b = 6

3b = 6

b = 6/3 = 2

Therefore, a = 0, b = 2.

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use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: