Jack and jill ran a 200 meter race. jill ran the race in in 25 seconds and won by 1010 âmeters; that is jack had run only 190190 meters when jill crossed the finish line. they decide to raceâ again, but this time jill starts 1010 meters behind the starting line. assuming that both runners run at the same pace asâ before, who will win the second race and by how manyâ seconds?

the speed of jack = 190m/25s = 7.6 m/s
the speed of jill = 200m/25s = 8 m/s 

the distance travelled by jack in 2nd race= 200m 
the distance travelled by jill in 2nd race= 210m 

the time taken by jack in 2nd race = 200m/(7.6 m/s) = 26.3158 s
the time taken by jill in 2nd race = 210m/(8 m/s) = 26.25 s

therefore jill will still win and lead by 26.3158s – 26.25s = 0.0658 seconds

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x