Will mark branliest, follow you, and say ur the best on ur profile question 1: multiply (3) × (−4) × (2). a. 48 b. 24 c. 4 d. 48 question 2: pauline spent $7.50 every day for 3 days. which expression is the best choice to her determine the total amount of money she spent? a. (7.50) × (−3) = −22.50; she spent $22.50. b. (−7.50) × (3) = −22.50; she spent $22.50. c.(−7.50) × (−3) = 22.50; she spent $22.50. d. (7.50) × (3) = 22.50; she spent $22.50. question 3: without multiplying, determine the sign of the product (−247,634) × (183,758). a. the sign of the product is positive because a negative multiplied by a positive is a positive. b. the sign of the product is negative because a negative multiplied by a positive is a negative. c. the sign of the product is negative because the first number is negative. d. the sign of the product is positive because the second number is positive. question 4: multiply 2 4/5 x -5 2/3 (the - sign equals negative) you sosososososo much! you're a lifesaver!

Asystem of linear equations with more equations than unknowns is sometimes called an overdetermined system. can such a system be consistent? illustrate your answer with a specific system of three equations in two unknowns. choose the correct answer below. a. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 6 b. no, overdetermined systems cannot be consistent because there are fewer free variables than equations. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 12 c. yes, overdetermined systems can be consistent. for example, the system of equations below is consistent because it has the solution nothing. (type an ordered pair.) x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 8 d. no, overdetermined systems cannot be consistent because there are no free variables. for example, the system of equations below has no solution. x 1 equals 2 comma x 2 equals 4 comma x 1 plus x 2 equals 24