The total weight of 6 pieces of butter and a bag of sugar is 3.8 ib. if the weight of the bag of sugar is 1.4 ib, what is the weight of each piece of butter?

0.4 lbs each.

Given:

Question:

What is the weight of each piece of butter?

The Process:

The two steps for obtaining the weight of each piece of butter are as follows:

Step-1: the total amount of butter is the total bag of butter and sugar subtracted by the weight of the bag of sugar.

Step-2: the total amount of butter divided by the number of pieces of butter is the the weight of each piece of butter.

Let's also consider the following quick steps.

Quick steps:

Therefore, the weight of each piece of butter is 0.4 lbs.

Keyword: the total weight, 6 pieces of butter, a bag of sugar is 3.8 Ib, if the weight of the bag of sugar is 1.4 Ib, each piece, subtracted, divide

The weight of each piece of butter is .

Further explanation:

The total weight of pieces of butter and the weight of a bag of sugar is equal to .

It is given that the weight of the bag of sugar is .

Now, let the weight of each piece of butter to be .

Then the weight of pieces of butter is .

Therefore, the total weight of pieces of butter and one bag of sugar is calculated as,

Given that total weight of pieces of butter and one bag of sugar is equal to .

Then, the total weight in the form of an equation can be written as,

Subtract on both sides of the above equation as follows:

Now, divide both sides of above equation by to obtain the value of as follows:

Thus, the weight of each piece of butter is .

Learn more:

1. Linear equation application

2. To solve one variable linear equation

3. Fractional expression simplification

Answer details

Grade: Middle School

Subject: Mathematics

Chapter: Linear equations

Keywords: Weight, pieces, butter, bag, sugar, total, lbs, equations, algebraic equations, linear, subtract, , , divide, total weight, each piece of butter.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )