Find three ordered pairs that satisfy the equation 4x+ 2y=8

X = 0 ;
2y = 8 ;
y = 4 ;
( 0 ; 4 ) 
x = - 1 ;
-4 + 2y = 8 ;
2y = 12 ;
y = 6 ;
( - 1 ; 6 )
x = 1 ;
4 + 2y = 8 ;
2y = 4 ;
y = 2 ;
( 1 ; 2 ) ;
The three ordered pairs are ( 0 ; 4 ) ; ( - 1 ; 6 ) ; ( 1 ; 2 ) .

The answer is