Iam doing mathematics right now and i need with a few of points walk me through the problem are the 1. 1/4 - 7/10 2. 2/3 - 1/2

For both of these you want to find a common factor
1. 10(1)-  4(7)       the easiest way to do this you multiply 4*10 for a common
    10(4)   4(10)     factor of 40. You multiply the same number on top and on
10 - 28 = -18        and on the bottom to keep the same value (whatever you do
40   40     40        on the bottom you do on the top). This let's you have the 
1. -18/40              same denominator so you can just subtract the numbers.

2. 2(2)- 3(1)
    2(3)  3(2)
     4  -  3 = 1
     6  -  6    6
2. 1/6

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12