Mathematics, 01.07.2019 16:40, jude3412
Find all points having an x coordinate of 1 whose distance from the point (-3,-6) is 5
Answers: 1
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ -3}}\quad ,&{{ -6}})\quad % (c,d) &({{ 1}}\quad ,&{{ y}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ 5=\sqrt{[1-(-3)]^2+[y-(-6)]^2}\implies 5=\sqrt{(1+3)^2+(y+6)^2} \\\\\\ 5=\sqrt{16+y^2+12y+36}\implies 5^2=16+y^2+12y+36 \\\\\\ 25=y^2+12y+52\implies 0=y^2+12y+27 \\\\\\ 0=(y+9)(y+3)\implies y= \begin{cases} -9\\ -3 \end{cases}](/tpl/images/0039/3627/fd70f.png)
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Find all points having an x coordinate of 1 whose distance from the point (-3,-6) is 5...
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