Bob is trying to decide between two cell phone plans. plan a has no flat fee, but the user must pay $10 cents per minute on the phone. plan b requires a one-time fee of $20 but only requires a payment of $5 cents per minute on the phone. what is the minimum whole number of minutes bob has to use the phone for to make plan b the cheaper plan? plz asap

Let x be the number of minutes that Bob anticipates using. Plan A costs 10x cents, while Plan B costs 2000 + 5x cents. We therefore have the inequality

2000+5x < 10x

2000 < 5x

400 < x.

The smallest integer x such that 400 < x is 401. Therefore, Bob must use at least 401 minutes to make Plan B cheaper.

r(0,90)(x,y) . t(-5,0)

last option

step-by-step explanation:

∆def to ∆d"e"f"

- rotate 90 counterclockwise degrees

- then translated 5 to the left (x --> x - 5)

answer is the last option