Starting from 300 feet away, a car drives toward you. it then passes by you at a speed of 48 feet per second. the distance dd (in feet) of the car from you after tt seconds is given by the equation d=|300−48t|d=|300−48t|. at what times is the car 60 feet from you?

we know that

The distance d (in feet) of the car from you after t seconds is given by the equation

Find the times t for

substitute the value of d in the equation

Solve for t

There are two solutions

First Solution

Second Solution

therefore

the answer is

At the time and at the time

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

i would need to see the dot plot : )