Mathematics

Mathematics, 01.09.2019 17:00, queen3574

Consider the function f(x) = 8 − 3x2. find the value of f(x) when x = 3 and select the correct answer below. -19 -10 26 35

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Mathematics, 17.07.2019 01:00, khameleonjr10

Im so bad at math ! find the average rate of change from x = 7 to x = 14 for the function f(x) = 0.01(2)x and select the correct answer below. select one: a. 23.22 b. 35.84 c. 128 d. 163.84 ik the answer is not d. 163.84

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Mathematics, 22.07.2019 08:00, rhianna18

Me with 3 math ! i will give 30 points and brainliest to whoever answers the best! 1. write the inverse function for the function, ƒ(x) = 1/2x + 4. then, find the value of ƒ -1(4). type your answers in the box. ƒ -1(x) = (answer) x (answer)(answer) ƒ -1(4) = (answer) 2. match each function with the expression representing its inverse function. match one of the numbers with the correct letter. 1. y = x - 4 2. g(x) = -0.5x 3. k(x) = x 4. p(x) = x + 4 5. h(x) = 4x 6. ƒ(x) = x/2 a. 2x b. x + 4 c. x - 4 d. -2x e. 0.25x f. x 3. the graph of a function g is shown below. find its inverse. (picture below, my answer is not correct)

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Mathematics, 30.07.2019 20:50, jdjdjdjdjjffi7273

Show that the given set of functions is orthogonal on the indicated interval. find the norm of each function in the set. 1, cos nπ p x , n = 1, 2, 3, ; [0, p] for m ≠ n p cos nπ p x cos mπ p x dx 0 = 1 2 p cos (n − m)π p x + correct: your answer is correct. dx 0 = correct: your answer is correct. p 0 = correct: your answer is correct. for m = n p cos2 nπ p x dx 0 = p 1 2 + dx 0 = p 0 = correct: your answer is correct. also p 1 · cos nπ p x dx 0 = p 0 = and p 12 dx 0 = correct: your answer is correct. p 0 = correct: your answer is correct. so that cos nπ p x = correct: your answer is correct. and 1 =

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Mathematics, 31.07.2019 02:00, ceasar6071

Consider the function f(x)=8-3x^2. find the value of f(x) when x=3 and select the correct answer below. a.-19 b.-10 c.26 d.35

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Consider the function f(x) = 8 − 3x2. find the value of f(x) when x = 3 and select the correct answe...

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