Mis the midpoint of fg. use the given information to find the missing measure or value. fm=3x-5, mg=5x-6: find fg

Since M is exactly between F and G, FM=FG.

Therefore, you can set the two expressions equal to each other. Solve.
3x-5=5x-6
5x-3x=6-5
2x=1
x=1/2

Now that we've found x, we can plug that into one of the expressions and multiply the result by two to find the length of the whole line.

a - base

b - exponent

so,

the base is 8the exponent is 3the exponent tells you to multiply 8 together three timesthe expanded form is 8*8*8