Kent has a collection of pennies and nickels with a value of 1.98$. the number of pennies he has is five less than twice the number of nickels. how many of each coin does kent have? 1 define your variables ,- what are you solving for 2 set up equations - using the information given 3 solve the system using your method of choice

Answer with Step-by-step explanation:

We are given that:

1. Let p be the number of pennies

and n be the number of nickles

2. Then, p=2n-5

1 pennie=$0.01

1 nickle=$0.05

0.01p+0.05n=1.98

Multiplying both sides by 100,we get

p+5n=198

3. Putting p=2n-5 in p+5n=198,we get

2n-5+5n=198

7n=198+5

7n=203

n=29

Putting value of n in p=2n-5, we get

p=2×29-5

p= 58-5

p= 53

Hence, Number of pennies=53

and number of nickle=29

provide more details to solve it

step-by-step explanation:

answer: 12x^2+6x

step-by-step explanation:

6x does not equal 24x. hope it works!