What is the area of a triangle with vertices at (–2, –1), (4, –1), (6, 5)? a. 6 square units b. 9 square units c. 18 square units d. 36 square units

  C.  18 square units

Step-by-step explanation:

The bottom edge is horizontal, so its length is easily determined to be 6 by subtracting one end-point x-coordinate from the other.

Similarly, the height is easily determined to be 6, as that is the difference between the y-values of the base line and the opposite vertex.

The area is half the product of these dimensions:

  A = (1/2)bh = (1/2)(6 units)(6 units) = 18 square units

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

i you goofed up when writing this, because hnot is not a word minusf is not either. i cannot answer   because of that.

step-by-step explanation: