Please help me with this problem:Factor completely. x^2+3x−18Enter your answer in the boxes. x^2+3x−18= (___ ) (___ )

To factor the quadratic equation, use the quadratic formula.

To a quadratic equation ax² + bx + c = 0, the quadratic formula is:

Given the quadratic equation x² + 3x - 18 = 0, the coefficients are:

a = 1

b = 3

c = -18

Substituting the coefficients and solving the equation:

So, the roots are: -6 and 3.

If a quadratic equation has roots x₁ and x₂, then the equation in the factored form is (x - x₁)(x - x₂).

So,

x² + 3x - 18 = (x - 3)(x + 6).

(x - 3)(x + 6).

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).