Hi Guys I'm stuck on this question

write x^2-4x+2 in the form (x-A)^2+B

(x-2)^2-2

Step-by-step explanation:

x^2-4x+2

take the x out

x(x-4) + 2

(x-2)^2-2

because (x-2)^2 is

x^2-4x+4

its like completing the square

(x-2)² -2

Step-by-step explanation:

Consider that (a+b)² = a²+2ab+b²

To find the form (x-A)²+B compare  x²-4x+2 with a²+2ab+b²

x² - 4x +2

a² + 2 a b+ b², so a= x and b = (-2)

x²+ 2· x ·(-2)+ (-2)² -  2  = (x-2)² -2 is in the form (x-A)²+B

Check our

(x-2)² -2= (x²-2·2x+4)-2 = x²-4x +2 ✅

the image of (6, 9) under a dilation is (4, 6). the scale factor is

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.