Put the equation below into vertex form.

y=(x+9)(x+25)

(-17,-24)
Explanation: y= x^2+34x+225
a=1, b=34
X= - 34/2+1
x = -17
Y= (x+9)(x+25), x=-17
Y=-64
So vertex is (-17,-64)

If you put the equation into standard form and use point of symmetry formula to find the vertex you can answer the problem.

standard form:
y = ax^2 + bx + c
y = x^2 + 34x + 225
a=1 b=34 c=225

point of symmetry formula:
x = -b/2a
x = -34/2
x = -14

plug in x to find the vertex

y = (-14+9)(-14+25)
y = (-5)(11)
y = -55

vertex = (-14,-55)

vertex form
y = a(x-h)^2 + k [where (h,k) is the vertex]

so your answer is:

y = 1(x-(-14))^2 + (-55)

or

y = (x+14)^2 - 55

I hope this helps and is the BRAINLIEST!!

Good luck with your studies!

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm