In a box of coins there is currently 31 coins consisting of pennies dimes and quarters. The total number of pennies is equal to the total number of dimes, and the total value is $3.46. How many of each denomination of coin does he have?

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.

i think the answer is true

step-by-step explanation:

step-by-step explanation:

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