Write a real world situation for f of x equals 3 times 1. 06 to the x exponent plus 2. So that would look this f(x)=3(1. 06x) + 2, but the x next to 1. 06 is an exponent. I’m having a real tough time writing this into a real world situation and hope anyone can help me out asap. Thank you!

a reflection across the x-axis , followed by the by a reflection across the y-axis , and then a scale dilation of 0.5 .

i believe it's a.

i'm not sure on this one, most likely correct.

because that’s us why

no oblique asymptote

step-by-step explanation:

to find the oblique asymptote of f(x)

here numerator has degree 1 and denomintor degree 2

degree of numerator < degree of denominator

hence there is no oblique asymptote

when the degree of the denominator > that of the numerator, we saw that the value in the denominator got so much bigger, so quickly,   giving us a horizontal asymptote of the x-axis. or we can write

f(x) = a polynomial of x + a proper fraction.

in this case only we have oblique asymptotes but not when numerator has less degree.