Please solve with explanation high points

a. -2x^2 + 3x+5=y

b.-x^2 +5x-4=y

c.-x^2 +6x-12=y

Step-by-step explanation:

a.y=-2x^2 +bx+c

the points P and Q lie on curve

=> b=3, c=5

b. delta = b^2 +4c

x1= =4

=> =8

x2==1

=>2=b+

suppose : = a

=>

=> a=-3

b=5

a=-3 =>   =-3 => b^2 +4c =9 =>5^2 +4c=9 => c=-4.

c.vertex (3;-3)

=3 => b =6

= =-3 =>-b^2+4ac=12 => c=-12.

a

step-by-step explanation:

i need the pts ignore this answer

step-by-step explanation:

de-gf

hj=3x+20

ji=15x-64