Given: ABCD is a rectangle. Prove: ΔABC is congruent to ΔCDA ABDC is a rectangle.
ABCD is a parallelogram. AB is congruent to DC and BC is congruent to DA AC is congruent to AC ΔABC is congruent to ΔCDA Given Definition of a rectangle. Opposite sides of a parallelogram are congruent. _ _
A. Symmetric Property of congruent; SAS
B. Reflexive Property of congruent to; SAS
C. Symmetric Property of congruent; SSS
D. Reflexive Property of congruent; SSS

D

3. Reflexive Property of (Congruence) ≅

4. SSS (Side to Side to Side Congruence rule)

Step-by-step explanation:

this is D reflexive property of SSS

3. Any geometric figure compared to itself is congruent to itself so this is why:

4. Since we have a parallelogram, therefore we can say:

Both triangles ABC and CDA satisfy the side to side to side congruence, since their 3 sides are congruent.

So, It's D.

P.S.

Notice that the angle measure information is not included in the data above that's why we cannot say it is SAS congruence.