Find the area of the yellow region, and no the answer to this exact question before was not correct. Thank you!

3.9 in²

Step-by-step explanation:

The shape is constructed of 2 semicircles (with diameter of 6 in) inside a square.  Therefore, to calculate the yellow region, subtract the area of the semicircles (which form a circle) from the area of the square, then halve the answer.

Area of a square =  ( is the length of one side)

Given:

⇒ area of the square = 6² = 36 in ²

Area of a circle =

Diameter of a circle = 2r

(where r is the radius)

Given:

⇒ area of the circle = × 3² = 9 in²

Area of yellow region = (area of square - area of circle) ÷ 2

                                    = (36 - 9) ÷ 2

                                    = 3.9 in² (nearest tenth)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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