Whats (x-3/4)^2 - 5 = 4 using the square root property? please have an explanation; will give brainliest

-9/4 and 15/4

  x = {-9/4, 15/4}

Step-by-step explanation:

To use the square root property to solve the quadratic, you need to get it to a form where the square root function can be usefully applied. That will mean having a square of a binomial on one side of the equal sign, and a constant on the other side of the equal sign.

We can get that from the given equation by adding 5 to both sides.

  (x -3/4)^2 -5 = 4 . . . . . . given

  (x -3/4)^2 = 9 . . . . . . . add 5 to get the square by itself

  x -3/4 = ±3 . . . . . . . . . take the square root

  x = ±3 +3/4 = {-9/4, 15/4} . . . . add 3/4 and expand the result

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

in which figure is point g a centroid