PLEASE HELP ASAP! 100 PTS! In a bag of candy, the probability that an orange candy is chosen is 0.55 and the probably that a green is chosen is 0.45. A person reaches into the bag of candy and chooses two. If X is the number of green candy pieces chosen, find the probability that has 0, 1, or 2 green pieces chosen.

answer: 7270

step-by-step explanation:

i am unable to solve this problem

step-by-step explanation:

hreryryrranswer:

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560