Solve the following problem. Give the equation using x as the variable, and give the answer. The sum of three times a number and 8 more than the number is the same as the difference between −22 and twice the number. What is the number?
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Part 1
Write the equation using x as the variable. Choose the correct equation below.
A.
3x+(x+8)=−22−2x
B.
3x−8x=2x−(−22)
C.
3x−8x=−22−2x
D.
3x+(x+8)=2x−(−22)

A. 3x + (x+8) = -22 - 2x

Step-by-step explanation:

Let the number equal x.

Set up the first half of the equation.

The sum of three times the number and 8 more than the number can be written as:

3x + (x+8)

Sum means that you add the components.

Set up the second half of the equation.

The difference between -22 and twice the number can be written as:

-22 - 2x

Difference means subtraction, and because -22 is written first, that is the number that you subtract from.

If you set the halves of the equation equal, you get:

3x + (x+8) = -22 - 2x

Therefore, the answer is A.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.