HELP O_O
Find the Roots of the polynomial equation!!!

2x^3+2x^2-19x+20=0

Your given polynomial has only one real root which is x= -4

Step-by-step explanation:

find any zero of the polynomial.

x-a divides the polynomial where a is a zero of polynomial:

So x+4 divides

If we factor out a two, we can use the quadratic formula.

2(x^2-3x+2.5) so we have x = (-(-3)+/-(9-4*1*2.5)^(1/2))/2*1)=(3+i) or (3-i)/2 .

Final

then x=-4, (3+i)/2, or (3-i)/2

555.99.

step-by-step explanation:

hope this

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%