Factorisation of 3p^3 + 9p^2- 15pq

STEP 1:Equation at the end of step 1 ((3 • (p3)) + 32p2) - 210p

STEP 2 :Equation at the end of step 2: (3p3 + 32p2) - 210p

STEP 3:STEP 4:

Pulling out like terms  4.1     Pull out like factors :   3p3 + 9p2 - 210p  =   3p • (p2 + 3p - 70) 

Trying to factor by splitting the middle term 4.2     Factoring  p2 + 3p - 70 The first term is,  p2  its coefficient is  1 .The middle term is,  +3p  its coefficient is  3 .The last term, "the constant", is  -70 Step-1 : Multiply the coefficient of the first term by the constant   1 • -70 = -70 Step-2 : Find two factors of  -70  whose sum equals the coefficient of the middle term,

which is   3 .     -70   +   1   =   -69     -35   +   2   =   -33     -14   +   5   =   -9     -10   +   7   =   -3     -7   +   10   =   3   That's itStep-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -7  and  10                      p2 - 7p + 10p - 70

Step-4 : Add up the first 2 terms, pulling out like factors :                    p • (p-7)              Add up the last 2 terms, pulling out common factors :                    10 • (p-7)Step-5 : Add up the four terms of step 4 :                    (p+10)  •  (p-7)             Which is the desired factorization

Final result : 3p • (p + 10) • (p - 7)

Step-by-step explanation:

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cross multiplying, we get :

⇒ (3) × (5) = (9) × (x)

⇒ 15 = 9x