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Triangle ABC with vertices A(-2, -3), B(5, -1), and C(2, 2) is translated by (x, y) → (x - 1, y + 2). Then the image, triangle A'B'C', is translated by (x, y) + (x + 2, y - 1), resulting in A"B"C".
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Triangle ABC with vertices A(-2, -3), B(5, -1), and C(2, 2) is translated by (x, y) → (x - 1, y + 2)...
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