I don't know how to solve this problem.

Length of the rectangular photo = 22 inches

Width of the rectangular photo = 20 inches

Since, width of the frame outside the photo = x inches

Therefore, increase in length and width of the photo with frame = (x + x)

                                                                                                          = 2x inches

Length of the photo with frame = (22 + 2x) inches

Width of the photo with frame = (20 + 2x) inches

Combined Area of the photo in the frame = Length × Width

                                                                     = (22 + 2x)(20 + 2x)

                                                                     = 22(20 + 2x) + 2x(20 + 2x)

                                                                     = 440 + 44x + 40x + 4x²

                                                                     = 4x² + 84x + 440

Therefore, polynomial representing the combined area of the photo in the frame will be (4x² + 84x + 440) square inches.

If width of the frame = 4 inches

Combined area of the photo = 4(4)² + 84(4) + 440

                                                = 840 square inches

$75.00

step-by-step explanation:

i = prt

i = 1,5000 * 0.025 * 2

i = 75