Solve for x: (3x-2)(x+1)=18x+4

x = 6 , -1/3

Step-by-step explanation:

Use foil method

(3x -2)(x + 1) = 3x*x + 3x*1 + (-2)*x + (-2)*1

                   = 3x² + 3x - 2x - 2   {Combine like terms}

                    =3x² + x - 2

(3x -2)(x + 1) = 18x + 4

3x² + x -2 = 18x + 4

Subtract 18x  to both sides

3x² + x - 18x - 2 = 4

3x² - 17x - 2    = 4

Subtract 4 from both sides

3x² - 17x -2 -4 = 0

3x² - 17x - 6 = 0

Sum = -17  

Product = (-6)*3 = -18

Factors = 1 , (-18)                 {1*(-18)=-18  ; 1 +(-18) = -17}

3x² - 18x + x - 6 = 0

3x(x - 6) + (x -6) = 0

(x - 6)(3x + 1) = 0

x - 6 = 0          ; 3x + 1 = 0

   x =  6          ;         3x = -1

                                  x = -1/3

x = 6 , (-1/3)

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

w'x is 0.

hope it