Learning task3:A. Change the following into the form of f(x) = mx + b 1.y-3x=7
2. 2x + 4y =8
3. -x + y =5
4.y + 5 = -2x
5. 3x + 2y - 4 = 0

1. f(x) = 3x + 7

2.

3. f(x) = x + 5

4. f(x) = -2x - 5

5.

Step-by-step explanation:

Rearrange all the equations to make y the subject,
then substitute f(x) for y:

1.   y - 3x = 7

Add 3x to both sides:

⇒ y = 3x + 7

⇒ f(x) = 3x + 7

2.   2x + 4y = 8

Subtract 2x from both sides:

⇒ 4y = -2x + 8

Divide both sides by 4:

⇒

⇒

3.   -x + y = 5

Add x to both sides:

⇒ y = x + 5

⇒ f(x) = x + 5

4. y + 5 = -2x

Subtract 5 from both sides:

⇒ y = -2x - 5

⇒ f(x) = -2x - 5

5.   3x + 2y - 4 = 0

Subtract 3x from both sides:

⇒ 2y - 4 = -3x

Add 4 to both sides:

⇒ 2y = -3x + 4

Divide both sides by 2;

⇒

⇒

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

my acc plz

step-by-step explanation: