Solve each system using the elimination method
3x+8y=2
4x-2y=-10

(-2, 1)

Step-by-step explanation:

3x +8y = 2

4x - 2y = -10

First, you would want to find common factors by changing the equations. In this case, it's much easier to change one of the equations by multiplying the bottom equation by 4. It will look like this:

4(4x - 2y = -10)  which will turn into:

16x - 8y = -40

*That will give us -8, which will cancel out the top equation's "y"s*

Now it will look like this:

3x + 8y = 2

16x - 8y = -40

Now, treat ^this as an addition problem.

You will get:

19x = -38

And x = -2

Now to solve for y, you do the same thing starting from the beginning, except cancel out the x

The answer is: y = 1

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐