I dont think my answer is correct pls help me out

Let us solve all the given 4 equations using the table , the equation which satisfies the conditions will be correct according to the table , We will use the relation x = -3, when y = 13 , which means if we put the value of x as -3 , we should get the value of y = 13 ,

➲ Solving for A) y = 3x:

‎ㅤ‎ㅤ‎ㅤ➙ y = 3x

‎ㅤ‎ㅤ‎ㅤ➙ y = 3 × -3

‎ㅤ‎ㅤ‎ㅤ➙ y = -9

This equation is not correct !

➲ Solving for B ) y = 6x + 4:

‎ㅤ‎ㅤ‎ㅤ➙ y = 6x +4

‎ㅤ‎ㅤ‎ㅤ➙ y = 6 × ( -3 ) + 4

‎ㅤ‎ㅤ‎ㅤ➙ y = -18 +4

‎ㅤ‎ㅤ‎ㅤ➙ y = -14

This equation is not correct!

➲ Solving for C) y = -3x + 4:

‎ㅤ‎ㅤ‎ㅤ➙ y = 3x +4

‎ㅤ‎ㅤ‎ㅤ➙ y = -3 × ( -3 ) +4

‎ㅤ‎ㅤ‎ㅤ➙ y = 9 + 4

‎ㅤ‎ㅤ‎ㅤ➙ y = 14

This equation is correct !

➲ Solving for D ) y =-3x:

‎ㅤ‎ㅤ‎ㅤ➙ y = -3x

‎ㅤ‎ㅤ‎ㅤ➙ y = -3 × ( -3 )

‎ㅤ‎ㅤ‎ㅤ➙ y = 9

This one is not correct!

‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ‎ㅤ~Hence, the correct answer is C) y = -3x +4

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2