Hey can someone help I am stumped.

Add the two equations together to get:

4y = -4

Solve for y by dividing both sides by 4:

Y = -1

Now you have a value for y, solve for x in the first equation:

2x + 3(-1) = 7

2x -3 = 7

Add 3 to both sides:

2x = 10

Divide both sides by 2:

X = 5

x = 5 and y = -1

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)