Part A) Identify the angle relationship and setup your equation with the given expressions. Part B) What is the value of x? Show your work.

Part C) What is the measure of angle A, B, & C? Show your work and make sure to identify which is which.

please help this is 2 days overdue :(

  (A)  3(x +5) +(5x +15) +7x = 180

  (B)  x = 10

  (C)  A = 45°, B = 65°, C = 70°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  m∠A +m∠B +m∠C = 180°

  3(x +5) +(5x +15) +7x = 180 . . . . . substitute given expressions

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  15x +30 = 180 . . . . . . . . . . . . . simplify

  15x = 150 . . . . . . . . . . . . . . subtract 30

  x = 10 . . . . . . . . . . . . . . divide by 15

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The angle measures are found from the given expressions:

  m∠A = 3(x +5) = 3(10 +5) = 45

  m∠B = 5x +15 = 5(10) +15 = 65

  m∠C = 7x = 7(10) = 70

m∠A = 45°, m∠B = 65°, m∠C = 70°

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

true

step-by-step explanation: