Mathematics, 18.02.2022 03:50, jasminellenaee

2 Select the correct answer.
Which equation could be solved using this application of the quadratic formula?
-3 + 32 – 4(1)(24)
2(1)
I=
OA. 12 +61 + 24 = 3.0
OB. 3.12 + 3x + 24 = 3
OC. 2 + 3r - 24 = 3
OD. 12 +31 + 24 = 3
Reset
Next

Answers: 1

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2 Select the correct answer. Which equation could be solved using this application of the quadratic formula? -3 + 32 – 4(1)(24) 2(1) I= OA. 12 +61 + 24 = 3.0 OB. 3.12 + 3x + 24 = 3 OC. 2 + 3r - 24 = 3 OD. 12 +31 + 24 = 3 Reset Next

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2 Select the correct answer.
Which equation could be solved using this application of the quadratic formula?
-3 + 32 – 4(1)(24)
2(1)
I=
OA. 12 +61 + 24 = 3.0
OB. 3.12 + 3x + 24 = 3
OC. 2 + 3r - 24 = 3
OD. 12 +31 + 24 = 3
Reset
Next