Analia is a school district manager. Here are some details about two schools in her district for the last school year: School ASchool B
Number of students
3000
30003000
4000
40004000
Number of teachers
190
190190
380
380380
Graduation rate
86
%
86%86, percent
90
%
90%90, percent
Budget per student
$
10
,
500
$10,500dollar sign, 10, comma, 500
$
10
,
000
$10,000dollar sign, 10, comma, 000
% of students in sports club
62
%
62%62, percent
68
%
68%68, percent
Number of sports medals won
9
99
7
77
SAT average
1200
12001200
1050
10501050
SAT range (max-min)
900
900900
700
700700
Analia wants to know which school has the lower SAT range relative to the resources invested per student (lower, as SAT range is a measure of inequality, which we want to minimize as much as possible).
1) Analia thought of two different ways to define this quantity. Identify these two definitions among the following options.

idk

step-by-step explanation:

do it yourself, cause that made me do it myself today, in english!

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)