![side*side = \dfrac{1}{2}b*h\\\\\\x*x=\dfrac{1}{2}*(x+1)(x+2)\\x^{2}=\dfrac{1}{2}[x*x +x*2+1*x+1*2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+2x+x+2]\\\\\\x^{2}=\dfrac{1}{2}[x^{2}+3x+2]\\\\\\Multiply \ both \ sides \ by \ 2\\\\2x^{2}=x^{2}+3x+2\\\\2x^{2}-x^{2}-3x-2 = 0](/tpl/images/2658/7885/6867b.png)
The area of the triangle is eqaula to the sqare show that x²-3x-2=0
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Mathematics, 14.02.2022 21:40, victoriacarr638
The area of the triangle is eqaula to the sqare show that x²-3x-2=0
Answers: 3
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